# Chapter 1 - Section 1.3 - Exponents, Order of Operations, and Variable Expressions - Exercise Set - Page 28: 39

$\dfrac{|6-2|+3}{8+2\cdot5}=\dfrac{7}{18}$

#### Work Step by Step

$\dfrac{|6-2|+3}{8+2\cdot5}$ First, perform the operation inside the absolute value bars in the numerator and the product in the denominator: $\dfrac{|6-2|+3}{8+2\cdot5}=\dfrac{|4|+3}{8+10}=...$ Now, evaluate the sums both in the numerator and the denominator: $...=\dfrac{4+3}{8+10}=\dfrac{7}{18}$

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