#### Answer

$\dfrac{|6-2|+3}{8+2\cdot5}=\dfrac{7}{18}$

#### Work Step by Step

$\dfrac{|6-2|+3}{8+2\cdot5}$
First, perform the operation inside the absolute value bars in the numerator and the product in the denominator:
$\dfrac{|6-2|+3}{8+2\cdot5}=\dfrac{|4|+3}{8+10}=...$
Now, evaluate the sums both in the numerator and the denominator:
$...=\dfrac{4+3}{8+10}=\dfrac{7}{18}$