## Algebra: A Combined Approach (4th Edition)

$\dfrac{15-|3-1|}{12-3\cdot2}=\dfrac{13}{6}$
$\dfrac{15-|3-1|}{12-3\cdot2}$ In the numerator, evaluate first the operation inside absolute value bars and then evaluate the substraction. In the denominator, evaluate the product first and after that, the substraction: $\dfrac{15-|3-1|}{12-3\cdot2}=\dfrac{15-|2|}{12-6}=\dfrac{13}{6}$