Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 1 - Section 1.3 - Exponents, Order of Operations, and Variable Expressions - Exercise Set: 40

Answer

$\dfrac{15-|3-1|}{12-3\cdot2}=\dfrac{13}{6}$

Work Step by Step

$\dfrac{15-|3-1|}{12-3\cdot2}$ In the numerator, evaluate first the operation inside absolute value bars and then evaluate the substraction. In the denominator, evaluate the product first and after that, the substraction: $\dfrac{15-|3-1|}{12-3\cdot2}=\dfrac{15-|2|}{12-6}=\dfrac{13}{6}$
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