## Algebra: A Combined Approach (4th Edition)

$3[4+3(6-4)]=30$
$3[4+3(6-4)]$ Let's start by performing (inside-out) the operations inside the parentheses: $3[4+3(6-4)]=3[4+3\cdot2]=...$ Now, evaluate the product inside the brackets and then, the sum that will result, also inside the brackets. Then, finally, evaluate the product to finish the problem: $...=3[4+6]=3[10]=30$