Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 1 - Section 1.3 - Exponents, Order of Operations, and Variable Expressions - Exercise Set: 42

Answer

$\dfrac{3+6(8-5)}{4^{2}+2}=\dfrac{7}{6}$

Work Step by Step

$\dfrac{3+6(8-5)}{4^{2}+2}$ Our first step wil be to perform the operation inside the parentheses in the numerator and to evaluate the exponential expression in the denominator: $\dfrac{3+6(8-5)}{4^{2}+2}=\dfrac{3+6(3)}{16+2}=...$ Now, in the numerator, evaluate the product and after that, the sum. In the denominator, evaluate the sum. At the end, simplify if possible: $...=\dfrac{3+18}{18}=\dfrac{21}{18}=\dfrac{7}{6}$
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