## Algebra: A Combined Approach (4th Edition)

$\dfrac{19-3\cdot5}{6-4}=2$
$\dfrac{19-3\cdot5}{6-4}$ First, evaluate the product in the numerator and after that, the substraction that will remain in the numerator: $\dfrac{19-3\cdot5}{6-4}=\dfrac{19-15}{6-4}=\dfrac{4}{6-4}=...$ Finally, evaluate the substraction in the denominator and then, the division: $...=\dfrac{4}{2}=2$