## Algebra: A Combined Approach (4th Edition)

$\dfrac{3+3(5+3)}{3^{2}+1}=\dfrac{27}{10}$
$\dfrac{3+3(5+3)}{3^{2}+1}$ First, perform the operation inside the parentheses in the numerator: $\dfrac{3+3(5+3)}{3^{2}+1}=\dfrac{3+3(8)}{3^{2}+1}=...$ Now, evaluate the product in the numerator and after that, the sum: $...=\dfrac{3+24}{3^{2}+1}=\dfrac{27}{3^{2}+1}=...$ Finally, in the denominator, evaluate the exponential expression and then the sum: $...=\dfrac{27}{9+1}=\dfrac{27}{10}$