Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-6 Natural Logarithms - Practice and Problem-Solving Exercises - Page 481: 27

Answer

$m=\dfrac{e^8-3}{2}$

Work Step by Step

Recall: $$\ln{a}=y \longleftrightarrow e^y=a$$ Use the definition above to obtain: \begin{align*} \ln{\left(2m+3\right)}&=8\\\\ e^8&=2m+3\\\\ e^8-3&=2m\\\\ \frac{e^8-3}{2}&=m \end{align*} Check: \begin{align*} \ln{\left(2\left(\frac{e^8-3}{2}\right)+3\right)}&\stackrel{?}=8\\\\ \ln{\left(e^8-3+3\right)}&\stackrel{?}=8\\\\ \ln{\left(e^8\right)}&\stackrel{?}=8\\\\ 8&\stackrel{\checkmark}=8\end{align*}
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