Answer
$x=\dfrac{e^{36}+1}{4}$
Work Step by Step
Recall:
$$\ln{a}=y \longleftrightarrow e^y=a$$
Use the definition above to obtain:
\begin{align*}
\ln{(4x-1)}&=36\\\\
e^{36}&=4x-1\\\\
e^{36}+1&=4x-1+1\\\\
e^{36}+1&=4x\\\\
\frac{e^{36}+1}{4}&=\frac{4x}{4}\\\\
\frac{e^{36}+1}{4}&=x
\end{align*}
