Answer
$1$
Work Step by Step
Recall:
$\log_a{\left(a^n\right)}=n$
Using the rule above, and knowing the the natural logarithms has base $e$, gives:
\begin{align*}
\dfrac{\ln{e^2}}{2}&=\dfrac{\log_e{\left(e^2\right)}}{2}\\\\
&=\dfrac{2}{2}\\\\
&=1
\end{align*}