Answer
$x=\pm \sqrt{e^{4.9}} \approx \pm 11.588$
Work Step by Step
Subtract $1.1$ from each side to obtain:
\begin{align*}
1.1+\ln{x^2}-1.1&=6-1.1\\
\ln{x^2}&=4.9
\end{align*}
Recall:
$$\ln{a} =y \longleftrightarrow e^y=a$$
Use the rule above to obtain:
\begin{align*}
\ln{x^2}&=4.9\\
e^{4.9}&=x^2
\end{align*}
Take the square root of both sides:
\begin{align*}
\pm\sqrt{e^{4.9}}&=x\\
\end{align*}
Use a calculator to obtain:
$$x\approx \pm11.588$$
