Answer
$0$
Work Step by Step
Recall:
(1) $n\cdot \ln{a}=\ln{a^n}$
(2) $\ln{a}+\ln{b}=\ln{(ab)}$
(3) $\ln{a}-\ln{b} = \ln{\left(\frac{a}{b}\right)}$
Use rule (1) above to obtain:
\begin{align*}
&=\ln{\left(8^2\right)}-\ln{\left(4^3\right)}\\
&=\ln{64}-\ln{64}\\
&=0
\end{align*}