Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-7 The Quadratic Formula - Practice and Problem-Solving Exercises - Page 245: 35

Answer

\begin{align*} \text{Discriminant: }& -23 \\\text{Number of Real Solutions: }& 0 \end{align*}

Work Step by Step

Using the properties of equality, the given equation, $ x+2=-3x^2 ,$ is equivalent to \begin{align*} 3x^2+x+2=0 \end{align*} In the equation above $a= 3 ,$ $b= 1 ,$ and $c= 2 .$ Using the Discriminant Formula which is given by $b^2-4ac,$ the value of the discriminant is \begin{array}{l}\require{cancel} & 1^2-4(3)(2) \\&= 1-24 \\&= -23 \end{array} Since the discriminant is less than $0,$ then there is no real solution. Hence, \begin{align*} \text{Discriminant: }& -23 \\\text{Number of Real Solutions: }& 0 \end{align*}
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