Answer
\begin{align*}
\text{Discriminant: }&
0
\\\text{Number of Real Solutions: }&
1
\end{align*}
Work Step by Step
In the given equation,
\begin{align*}
-4x^2+20x-25=0
,\end{align*} $a=
-4
,$ $b=
20
,$ and $c=
-25
.$ Using the Discriminant Formula which is given by $b^2-4ac,$ the value of the discriminant is
\begin{array}{l}\require{cancel}
&
20^2-4(-4)(-25)
\\&=
400-400
\\&=
0
\end{array}
Since the discriminant is equal to $0,$ then there is $1$ real solution. Hence,
\begin{align*}
\text{Discriminant: }&
0
\\\text{Number of Real Solutions: }&
1
\end{align*}
