Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-7 The Quadratic Formula - Practice and Problem-Solving Exercises - Page 245: 31

Answer

\begin{align*} \text{Discriminant: }& 1 \\\text{Number of Real Solutions: }& 2 \end{align*}

Work Step by Step

Using the properties of equality, the given equation, $ -2x^2+7x=6 ,$ is equivalent to \begin{align*} -2x^2+7x-6=0 .\end{align*} In the equation above $a= -2 ,$ $b= 7 ,$ and $c= -6 .$ Using the Discriminant Formula which is given by $b^2-4ac,$ the value of the discriminant is \begin{array}{l}\require{cancel} & 7^2-4(-2)(-6) \\&= 49-48 \\&= 1 \end{array} Since the discriminant is greater than $0,$ then there are $2$ real solutions. Hence, \begin{align*} \text{Discriminant: }& 1 \\\text{Number of Real Solutions: }& 2 \end{align*}
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