Answer
\begin{align*}
\text{Discriminant: }&
0
\\\text{Number of Real Solutions: }&
1
\end{align*}
Work Step by Step
In the given equation,
\begin{align*}
x^2-12x+36=0
,\end{align*} $a=
1
,$ $b=
-12
,$ and $c=
36
.$ Using the Discriminant Formula which is given by $b^2-4ac,$ the value of the discriminant is
\begin{array}{l}\require{cancel}
&
(-12)^2-4(1)(36)
\\&=
144-144
\\&=
0
\end{array}
Since the discriminant is equal to $0,$ then there is $1$ real solution. Hence,
\begin{align*}
\text{Discriminant: }&
0
\\\text{Number of Real Solutions: }&
1
\end{align*}
