Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 678: 29

Answer

$10,987,286,400$

Work Step by Step

Use the formula $P(n,r)=\dfrac{n!}{(n-r)!}$. Here, we have $n=15$ and $r=10$ so substitute these values into the formula: above to obtain: $P(15,10)=\dfrac{15!}{(15-10)!}\\\\ P(15,10)=\dfrac{15!}{5!}\\\\ P(15,10)=\dfrac{15{\times}14{\times}13{\times}12{\times}11{\times}10{\times}9{\times}8{\times}7{\times}6{\times}5{\times}4{\times}3{\times}2{\times}1}{5{\times}4{\times}3{\times}2{\times}1}$ Cancel out common factors to get: $P(15,10)=15\times14\times13\times12\times11\times10\times9\times8\times7\times6 \\ P(15,10)=10,987,286,400$
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