Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 678: 26

Answer

$120$

Work Step by Step

Use the formula $P(n,r)=\dfrac{n!}{(n-r)!}$. Here we have $n=5$ and $r=4$.: Substitute these values into the formula above to obtain: $P(5,4)=\dfrac{5!}{(5-4)!}\\$ $P(5,4)=\dfrac{5!}{1!}\\$ $P(5,4)=\dfrac{5\cdot4\cdot3\cdot2\cdot1}{1}$ Cancel out the common factors to obtain: $P(5, 4) = 5\cdot4\cdot3\cdot2\\ P(5, 4) = 120$
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