Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 678: 23

Answer

$336$

Work Step by Step

Use the formula $P(n,r)=\dfrac{n!}{(n-r)!}$. Here we have $n=8$ and $r=3$: Substitute these values into the formula above to obtain: $P(8,3)=\dfrac{8!}{(8-3)!}\\$ $P(8,3)=\dfrac{8!}{5!}\\$ $P(8,3)=\dfrac{8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}{5\cdot4\cdot3\cdot2\cdot1}$ Cancel out common factors to obtain: $P(8, 3)= 8\cdot7\cdot6\\ P(8, 3)=336$
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