Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 678: 27

Answer

$60,480$

Work Step by Step

Use the formula $P(n,r)=\dfrac{n!}{(n-r)!}$. Here, $n=9$ and $r=6$ so substitute these values into the formula to obtain: $P(9,6)=\dfrac{9!}{(9-6)!}\\\\ P(9,6)=\dfrac{9!}{3!}\\\\ P(9.6)=\dfrac{9{\times}8{\times}7{\times}6{\times}5{\times}4{\times}3{\times}2{\times}1}{3{\times}2{\times}1}$ Cancel out common factors to get: $P(9,6)=9{\times}8{\times}7{\times}6{\times}5{\times}4\\ P(9, 6)=60480$
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