Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 678: 25

Answer

$6$

Work Step by Step

Use the formula $P(n,r)=\dfrac{n!}{(n-r)!}$. Here we have $n=8$ and $r=2$: Substitute these values into the formula above to obtain: $P(3,2)=\dfrac{3!}{(3-2)!}\\$ $P(3,2)=\dfrac{3!}{1!}\\$ $P(3,2)=\dfrac{3*2*1}{1}$ Cancel out the common factors to obtain: $P(8, 2) = 3\cdot2 = 6$
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