Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Mixed Review - Page 510: 63



Work Step by Step

In order to solve for d the proportion $\frac{6}{10}$=$\frac{z}{35}$, we must apply the Cross Products Property of a Proportion that states that if $\frac{a}{b}$=$\frac{c}{d}$, where b$\ne$0 and d$\ne$0, then ad=bc. We'll set a=6, b=10, c=z and d=35, and apply the Property. $\frac{6}{10}$=$\frac{z}{35}$ (6)(35)=(z)(10) 210=10z Then, to solve for a, we'll divide by 10 on both sides of the equation $\frac{210}{10}$=$\frac{10z}{10}$ z=$\frac{210}{10}$=21
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