Answer
(x-5)(x-12)
Work Step by Step
Given the polynomial
$x^{2}$ - 17x + 60
*** We break of the middle term into two factors that add to give -17 and multiply to give +60. The two numbers are -12 and -5.
$x^{2}$ - 5x - 12x + 60
We take the GCD of the first two and the GCD of the last two terms.
x(x-5) - 12(x-5)
We take (x-5) and factor it out which gives us.
(x-5)(x-12)
