Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Mixed Review - Page 510: 59

Answer

(x-5)(x-12)

Work Step by Step

Given the polynomial $x^{2}$ - 17x + 60 *** We break of the middle term into two factors that add to give -17 and multiply to give +60. The two numbers are -12 and -5. $x^{2}$ - 5x - 12x + 60 We take the GCD of the first two and the GCD of the last two terms. x(x-5) - 12(x-5) We take (x-5) and factor it out which gives us. (x-5)(x-12)
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