## Algebra 1

Given the polynomial $w^{2}$ + 15w + 44 *** We break of the middle term into two factors that add to give +15 and multiply to give +44. The two numbers are +11 and +4. $w^{2}$ + 11w + 4w + 44 We take the GCD of the first two and the GCD of the last two terms. w(w+11) +4(w+11) We take (w+11) and factor it out which gives us. (w+11)(w+4)