## Algebra 1

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Mixed Review - Page 510: 61

d=12

#### Work Step by Step

In order to solve for d the proportion $\frac{2}{3}$=$\frac{d}{18}$, we must apply the Cross Products Property of a Proportion that states that if $\frac{a}{b}$=$\frac{c}{d}$, where b$\ne$0 and d$\ne$0, then ad=bc. We'll set a=2, b=3, c=d and d=18, and apply the Property. $\frac{5}{6}$=$\frac{x}{15}$ (2)(18)=(d)(3) 36=3d Then, to solve for d, we'll divide by 3 on both sides of the equation $\frac{36}{3}$=$\frac{3d}{3}$ d=$\frac{36}{3}$=12

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