Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Mixed Review - Page 510: 62



Work Step by Step

In order to solve for d the proportion $\frac{5}{8}$=$\frac{a}{60}$, we must apply the Cross Products Property of a Proportion that states that if $\frac{a}{b}$=$\frac{c}{d}$, where b$\ne$0 and d$\ne$0, then ad=bc. We'll set a=5, b=8, c=a and d=60, and apply the Property. $\frac{5}{8}$=$\frac{a}{60}$ (5)(60)=(a)(8) 300=8a Then, to solve for a, we'll divide by 8 on both sides of the equation $\frac{300}{8}$=$\frac{8a}{8}$ a=$\frac{300}{8}$=$\frac{75}{2}$
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