## Algebra 1

Given the polynomial $t^{2}$ -3t - 28 *** We break of the middle term into two factors that add to give -3 and multiply to give -28. The two numbers are -7 and +4. $t^{2}$ -7t +4t - 28 We take the GCD of the first two and the GCD of the last two terms. t(t-7) +4(t-7) We take (t-7) and factor it out which gives us. (t-7)(t+4)