Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Mixed Review - Page 510: 60



Work Step by Step

In order to solve for x the proportion $\frac{5}{6}$=$\frac{x}{15}$, we must apply the Cross Products Property of a Proportion that states that if $\frac{a}{b}$=$\frac{c}{d}$, where b$\ne$0 and d$\ne$0, then ad=bc. We'll set a=5, b=6, c=x and d=15, and apply the Property. $\frac{5}{6}$=$\frac{x}{15}$ (5)(15)=(x)(6) 75=6x Then, to solve for x, we'll divide by 6 on both sides of the equation $\frac{75}{6}$=$\frac{6x}{6}$ x=$\frac{75}{6}$=$\frac{25}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.