Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Practice and Problem-Solving Exercises - Page 503: 24

Answer

(r+9)(r-3)

Work Step by Step

Given the polynomial $r^{2}$ + 6r - 27 *** We break of the middle term into two factors that add to give +6 and multiply to give -27. The two numbers are +9 and -3. $r^{2}$ + 9r - 3r - 27 We take the GCD of the first two and the GDC of the last two terms. r(r+9) -3(r+9) We take (r+9) and factor it out which gives us. (r+9)(r-3)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.