Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Practice and Problem-Solving Exercises: 24

Answer

(r+9)(r-3)

Work Step by Step

Given the polynomial $r^{2}$ + 6r - 27 *** We break of the middle term into two factors that add to give +6 and multiply to give -27. The two numbers are +9 and -3. $r^{2}$ + 9r - 3r - 27 We take the GCD of the first two and the GDC of the last two terms. r(r+9) -3(r+9) We take (r+9) and factor it out which gives us. (r+9)(r-3)
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