Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Practice and Problem-Solving Exercises: 19

Answer

$q^2-8q+12=(q-2)(q-6)$

Work Step by Step

$q^2-8q+12$ Factors of 12 | Sum of Factors $\ \ \ \ \ \ 1,12\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 13$ $\ \ \ \ \ \ 2,6\ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ 8\checkmark$ $\ \ \ \ \ \ 4,3\ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ 7$ Since the second term in the binomial is subtracted (or negative) and the third term is positive, the factors will both include subtraction. $q^2-8q+12=(q-2)(q-6)$ Use the FOIL method to check the answer. $(q-2)(q-6)=q^2-6q-2q+12=q^2-8q+12\checkmark$
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