## Algebra 1

$x^2+15x+56=(x+8)(x+7)$
$x^2+15x+56$ Factors of 56 | Sum of Factors $\ \ \ \ \ \ 1,56\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 57$ $\ \ \ \ \ \ 2,28\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 30$ $\ \ \ \ \ \ 4,14\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 18$ $\ \ \ \ \ \ 8,7\ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 15\checkmark$ Since all the terms in the binomial are added, the factors will both include addition. $x^2+15x+56=(x+8)(x+7)$ Use the FOIL method to check the answer. $(x+8)(x+7)=x^2+7x+8x+56=x^2+15x+56\checkmark$