Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Practice and Problem-Solving Exercises: 18

Answer

$r^2-11r+24=(r-8)(r-3)$

Work Step by Step

$r^2-11r+24$ Factors of 24 | Sum of Factors $\ \ \ \ \ \ 1,24\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 25$ $\ \ \ \ \ \ 2,12\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 14$ $\ \ \ \ \ \ 4,6\ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 10$ $\ \ \ \ \ \ 8,3\ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 11\checkmark$ Since the second term in the binomial is subtracted (or negative) and the third term is positive, the factors will both include subtraction. $r^2-11r+24=(r-8)(r-3)$ Use the FOIL method to check the answer. $(r-8)(r-3)=r^2-3r-8r+24=r^2-11r+24\checkmark$
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