## Algebra 1

$(y+1)(y+5)$
$y^2+6y+5$ Factors of 5 | Sum of Factors $\ \ \ \ \ \ 1,5\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 6$ Since all the terms in the binomial are added, the factors will both include addition. $y^2+6y+5=(y+1)(y+5)$ Use the FOIL method to check the answer. $(y+1)(y+5)=y^2+5y+1y+5=y^2+6y+5\checkmark$