Answer
$n^2-15n+56=(n-8)(n-7)$
Work Step by Step
$n^2-15n+56$
Factors of 56 | Sum of Factors
$\ \ \ \ \ \ 1,56\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 57$
$\ \ \ \ \ \ 2,28\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 30$
$\ \ \ \ \ \ 4,14\ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 18$
$\ \ \ \ \ \ 8,7\ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ 15\checkmark$
Since the second term in the binomial is subtracted (or negative) and the third term is positive, the factors will both include subtraction.
$n^2-15n+56=(n-8)(n-7)$
Use the FOIL method to check the answer.
$(n-8)(n-7)=n^2-7x-8x+56=n^2-15n+56\checkmark$
