## Algebra 1

$(x-5)(x-2)$
$x^2-7x+10=(x-5)(x-\underset\uparrow?)$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \$added to 5, must equal 7 $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \$multiplied by 5, must equal 10 Let y be ?. $y+5=7$ $y+5-5=7-5$ $y=2$ $5y=10$ $5y\div5=10\div5$ $y=2$