Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 35

Answer

The GCF is not $4$, it is $4x$. The factorization is not complete Result: $4x(x+3)(x^{2}+2)$

Work Step by Step

The GCF is not $4$, it is $4x$. The factorization is not complete $4x^{4}+12x^{3}+8x^{2}+24x=$ ...factor out the GCF. $=4x(x^{3}+3x^{2}+2x+6)$ ...factor by grouping. $=4x[x^{2}(x+3)+2(x+3)]$ ...factor again. $=4x(x+3)(x^{2}+2)$
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