## Algebra 1: Common Core (15th Edition)

The GCF is not $4$, it is $4x$. The factorization is not complete Result: $4x(x+3)(x^{2}+2)$
The GCF is not $4$, it is $4x$. The factorization is not complete $4x^{4}+12x^{3}+8x^{2}+24x=$ ...factor out the GCF. $=4x(x^{3}+3x^{2}+2x+6)$ ...factor by grouping. $=4x[x^{2}(x+3)+2(x+3)]$ ...factor again. $=4x(x+3)(x^{2}+2)$