Answer
$6y(10y^{2}-7)(y-5)$
Work Step by Step
$60y^{4}-300y^{3}-42y^{2}+210y=$
...factor out the GCF.
$=6y(10y^{3}-50y^{2}-7y+35)$
...factor by grouping.
$=6y[10y^{2}(y-5)-7(y-5)]$
...factor again.
$=6y(10y^{2}-7)(y-5)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 32
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