Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 23

Answer

$w(3w-2)(w^{2}+6)$

Work Step by Step

$3w^{4}-2w^{3}+18w^{2}-12w=$ ...factor out the GCF. $=w(3w^{3}-2w^{2}+18w-12)$ ...factor by grouping the first term with the third, and the second term with the last. $=w[3w(w^{2}+6)-2(w^{2}+6)]$ ...factor again. $=w(3w-2)(w^{2}+6)$
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