Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 25



Work Step by Step

$6q^{4}+3q^{3}-24q^{2}-12q=$ ...factor out the GCF. $=3q(2q^{3}+q^{2}-8q-4)$ ...factor by grouping. $=3q[q^{2}(2q+1)-4(2q+1)]$ ...factor again. $=3q(q^{2}-4)(2q+1)$ ...write $q^{2}-4$ as a difference of two squares. $=3q(q-2)(q+2)(2q+1)$
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