Answer
$9t(t-2)(t-8)$
Work Step by Step
$9t^{3}-90t^{2}+144t=$
...factor out the GCF.
$=9t(t^{2}-10t+16)$
...rewrite $-10t$ as $-8t-2t$.
$=9t(t^{2}-8t-2t+16)$
...factor by grouping.
$=9t[t(t-8)-2(t-8)]$
...factor again.
$=9t(t-2)(t-8)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 31
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