Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 31



Work Step by Step

$9t^{3}-90t^{2}+144t=$ ...factor out the GCF. $=9t(t^{2}-10t+16)$ ...rewrite $-10t$ as $-8t-2t$. $=9t(t^{2}-8t-2t+16)$ ...factor by grouping. $=9t[t(t-8)-2(t-8)]$ ...factor again. $=9t(t-2)(t-8)$
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