#### Answer

$g(5g^{2}+20)(g-1)$

#### Work Step by Step

$5g^{4}-5g^{3}+20g^{2}-20g=$
...factor out the GCF.
$=g(5g^{3}-5g^{2}+20g-20)$
...factor by grouping.
$=g[5g^{2}(g-1)+20(g-1)]$
...factor again.
$=g(5g^{2}+20)(g-1)$

Chegg costs money, GradeSaver solutions are free!

Published by
Prentice Hall

ISBN 10:
0133281140

ISBN 13:
978-0-13328-114-9

$g(5g^{2}+20)(g-1)$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.