Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 24



Work Step by Step

$5g^{4}-5g^{3}+20g^{2}-20g=$ ...factor out the GCF. $=g(5g^{3}-5g^{2}+20g-20)$ ...factor by grouping. $=g[5g^{2}(g-1)+20(g-1)]$ ...factor again. $=g(5g^{2}+20)(g-1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.