Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 532: 22

Answer

$4(2p^{2}+7)(p-4)$

Work Step by Step

$8p^{3}-32p^{2}+28p-112=$ ...factor out the GCF. $=4(2p^{3}-8p^{2}+7p-28)$ ...factor by grouping. $=4[2p^{2}(p-4)+7(p-4)]$ ...factor again. $=4(2p^{2}+7)(p-4)$
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