Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises: 35

Answer

The answer is $a^{\frac{1}{6}}$

Work Step by Step

To solve this $a^{\frac{2}{3}}$$\times$$a^{x}$ = $a^{\frac{5}{6}}$ $a^{x}$ = $\frac{a^{\frac{5}{6}}}{a^{\frac{2}{3}}}$ $a^{x}$ = $a^{\frac{5}{6}-\frac{2}{3}}$ $a^{x}$ = $a^{\frac{5}{6}-\frac{4}{6}}$ $a^{x}$ = $a^{\frac{1}{6}}$ --> since bases are equal, make the exponents equal x = $\frac{1}{6}$ Therefore the missing part is $a^{\frac{1}{6}}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.