## Algebra 1: Common Core (15th Edition)

$5^{9}$
To solve this $5^{2}$ $\times$ $5^{x}$ = $5^{11}$ $5^{x}$ = $\frac{5^{11}}{5^{2}}$ $5^{x}$ = $5^{11-2}$ $5^{x}$ = $5^{9}$ --> same base, bring the exponents down x=9 Therefore the missing part is $5^{9}$.