Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises: 34

Answer

The answer is $a^{-4}$

Work Step by Step

To solve this $a^{0}$=1 as any number with exponent 0 becomes 1 $a^{x}$ $\times$ $a^{4}$ = 1 $a^{x}$ $\times$ $a^{4}$ = $a^{0}$ $a^{x}$ = $\frac{a^{0}}{a^{4}}$ $a^{x}$ = $a^{0-4}$ $a^{x}$ = $a^{-4}$ --> same base, bring the exponents down x= -4 Therefore the missing part is $a^{-4}$.
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