Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 430: 44

Answer

The answer is 8$m^{\frac{2}{3}}$ + 16$m^{\frac{1}{3}}$

Work Step by Step

To solve this = 8$m^{\frac{1}{3}}$($m^{\frac{1}{3}}$+ 2) =( 8$m^{\frac{1}{3}}$$\times$$m^{\frac{1}{3}}$)+(8$m^{\frac{1}{3}}$$\times$2) = ( 8$m^{\frac{1}{3}+\frac{1}{3}}$) + ( 8$\times$2)($m^{\frac{1}{3}}$) = 8$m^{\frac{2}{3}}$ + 16$m^{\frac{1}{3}}$
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