Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 430: 45


The answer is -12$x^{6}$ + 40$x^{4}$

Work Step by Step

To solve this = -4$x^{3}$($3x^{3}$ - 10x) =( -4$\times$3)($x^{3}$$\times$$x^{3}$)+(-4$\times$-10)($x^{3}$$\times$x) = -12($x^{3+3})$+(40)($x^{3+1})$ = -12$x^{6}$ + 40$x^{4}$
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