Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 430: 32


The answer is $m^{-5}$

Work Step by Step

To solve this $m^{x}$ $\times$ $m^{-4}$ = $m^{-9}$ $m^{x}$ = $\frac{m^{-9}}{m^{-4}}$ $m^{x}$ = $m^{-9-(-4)}$ $m^{x}$ = $m^{(-9+4)}$ $m^{x}$ = $m^{-5}$ --> same base, bring the exponents down x=-5 Therefore the missing part is $m^{-5}$.
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