## Algebra 1: Common Core (15th Edition)

The answer is $2^{\frac{1}{2}}$
To solve this $2^{x}$ $\times$ $2^{\frac{1}{2}}$ = $2^{1}$ $2^{x}$ = $\frac{2^{1}}{2^{\frac{1}{2}}}$ $2^{x}$ = $2^{1-(\frac{1}{2})}$ $2^{x}$ = $2^{\frac{1}{2}}$ --> same base, bring the exponents down x= $\frac{1}{2}$ Therefore, the missing part is $2^{\frac{1}{2}}$.