Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 690: 8



Work Step by Step

Given : $\frac{z-3}{3z} \times \frac{z+8}{z+2}=\frac{z^{2}+8z-3z-24}{3z^{2}+6z}=\frac{z^{2}+5z-24}{3z^{2}+6z}=\frac{(z-3)(z+8)}{3z(z+2)}$
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