Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 690: 1


$6(x-2), where$ $x\ne-2$

Work Step by Step

Given : $\frac{6x^{2}-24}{x+2}= \frac{6(x^{2}-4)}{x+2}=\frac{6(x+2)(x-2)}{x+2}$ (Since $(a^{2}-b^{2})=(a+b)(a-b)$) $= 6(x-2)$ (After dividing out the common factor (x+2)) $6(x-2), where$ $x\ne-2$
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